Practicing Success
Practicing Success
CUET Preparation Today
If $f(x)=\left\{\begin{array}{cc}\frac{\tan \left(\frac{\pi}{4}-x\right)}{\cot 2 x}, & x \neq \frac{\pi}{4} \\ k, & x=\frac{\pi}{4}\end{array}\right.$ is continuous at $x=\frac{\pi}{4}$, then the value of 'k' is: |
1 2 $\frac{1}{2}$ $-\frac{1}{2}$ |
$\frac{1}{2}$ |
The correct answer is Option (3) - $\frac{1}{2}$ |
