If $(x -\frac{1}{x})= 7.5$, what is the value of $(x^2 + \frac{1}{x^2})$?
Answer & explanation
Correct answer: option 2
If $K-\frac{1}{K}=n$
then, $K^2+\frac{1}{K^2}$ = n2 + 2 × k × \(\frac{1}{k}\)
If $(x -\frac{1}{x})= 7.5$
The value of $(x^2 + \frac{1}{x^2})$ = 7.52 + 2
= $(x^2 + \frac{1}{x^2})$ = 56.25 + 2 = 58.25