If a - 1/(a - 4) = 6 Then find , (a - 4)3 - 1/((a - 4)^3)

Given = a - \(\frac{1}{a - 4}\) = 6

By subtracting 4 on both sides we get,

(a - 4) - \(\frac{1}{a - 4}\) = 6 - 4 = 2

(a - 4)³ - \(\frac{1}{(a - 4)^3}\) = 2³ + 3 × 2 = 14

 

Note - if x -  \(\frac{1}{x}\) = a

then x³ - \(\frac{1}{x^3}\) =  a³ + 3a