a b c d

c

$ \text{Debroglie Wavelength } \lambda = \frac{h}{p}$ $\frac{\lambda_1}{\lambda_2} = \frac{p_2}{p_1} = \frac{m_2}{m_1} \frac{v_2}{v_1} = 5 \frac{m_2}{m_1}$ $m_2 = \frac{m_1}{5} \frac{\lambda_1}{\lambda_2}= \frac{9.11 \times 10^{-31}}{5 \times 1.878\times10^{-4}} = 9.7 \times 10^{-28} kg$