A cylindrical vessel of radius 30 cm and height 42 cm is full of water. Its contents are emptied into a rectangular tub of length 75 cm and breadth 44 cm. The height (in cm) to which the water rises in the tub is: (Take π = $\frac{22}{7}$)
Answer & explanation
Correct answer: option 1
We know that,
Volume of cylindrical vessel = πr2h
The volume of rectangular tub = L × B × H
We have,
Radius of vessel = 30 cm
Height of vessel = 42 cm
Length of tub = 75 cm
Breadth of tub = 44 cm
Le the height of the rectangular tub = H
According to the question,
75 × 44 × H = \(\frac{22}{7}\) × 30 × 30 × 42
On solving further, = H = 36