A cylindrical vessel of radius 30 cm and height 42 cm is full of water. Its contents are emptied into a rectangular tub of length 75 cm and breadth 44 cm. The height (in cm) to which the water rises in the tub is: (Take π = $\frac{22}{7}$)

36

We know that,

Volume of cylindrical vessel = πr²h

The volume of rectangular tub = L × B × H

We have,

Radius of vessel = 30 cm

Height of vessel = 42 cm

Length of tub = 75 cm

Breadth of tub = 44 cm

Le the height of the rectangular tub = H

According to the question,

75 × 44 × H = \(\frac{22}{7}\) × 30 × 30 × 42

On solving further, = H = 36