A solid metallic sphere of radius 18 cm is melted and recast into a cylinder of radius 9 cm. What is the height of this cylinder?
Answer & explanation
Correct answer: option 4
Volume remains same for both figure
⇒ volume of sphere = volume of cylinder
⇒ \(\frac{4}{3}\) \(\pi \)r3 = \(\pi \)r22h
⇒ \(\frac{4}{3}\) \(\pi \)(18)3 = \(\pi \)(9)2h
⇒ 4 × 6 × (18)² = (9)2h
⇒ h = \(\frac{7776}{81}\) = 96 cm