The order and degree of differential equation are :
$x^2\frac{d^2y}{dx^2}-3\left(\frac{dy}{dx}\right)^3+y=0 $
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → order = 2, degree = 1
$x^2\frac{d^2y}{dx^2}-3\left(\frac{dy}{dx}\right)^3+y=0 $
Order = Highest order derivative = 2
Degree = Power of highest order derivative = 1