Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

The order and degree of differential equation are :

$x^2\frac{d^2y}{dx^2}-3\left(\frac{dy}{dx}\right)^3+y=0 $

Options:

order = 2

degree = 2

order = 3

degree = 2

order = 1

degree = 1

order = 2

degree = 1

Correct Answer:

order = 2

degree = 1

Explanation:

The correct answer is Option (4) → order = 2, degree = 1

$x^2\frac{d^2y}{dx^2}-3\left(\frac{dy}{dx}\right)^3+y=0 $

Order = Highest order derivative = 2

Degree = Power of highest order derivative = 1