A tap can fill a tank in 5\(\frac{1}{2}\) hours. Because of leakage, it took 8\(\frac{1}{4}\) hours to fill the tank. In how much hour will the leakage alone can empty 30% of the tank?

\(\frac{99}{20}\)

Leak's efficeincy = 6 - 4 = 2

Now → 

Leak will take = \(\frac{33}{2}\) × \(\frac{3}{10}\) = \(\frac{99}{20}\) hr to empty 30% of the tank.