Practicing Success
A policeman sees a chain snatcher at a distance of 500 m. He starts chasing the chain snatcher who is running at a speed of 5 m/s, while the policeman is chasing him at a speed of 15 m/s. Find the distance covered by the chain snatcher, when he is caught by the policeman. |
200 m 180 m 150 m 250 m |
250 m |
Distance between policeman and Chain Snatcher = 500 m Speed of Chain Snatcher = 5 m/sec & speed of policeman = 15 m/sec Relative speed = 15 - 5 = 10 m/sec Time taken by policeman to caught the Chain Snatcher = \(\frac{500}{10}\) = 50 sec Distance traveled by Chain Snatcher = 50 × 5 = 250 m |