If $1 + tan θ = \sqrt{3}$, then $\sqrt{3} cot θ -1$ = _________.
Answer & explanation
Correct answer: option 1
1 + tan θ = √3
tan θ = √3- 1
Now,
√3.cotθ - 1
= √3 × \(\frac{1}{√3- 1 }\) - 1
= √3 × \(\frac{√3+ 1}{2 }\) - 1
= \(\frac{√3+ 1}{2 }\)
If $1 + tan θ = \sqrt{3}$, then $\sqrt{3} cot θ -1$ = _________.
Correct answer: option 1
1 + tan θ = √3
tan θ = √3- 1
Now,
√3.cotθ - 1
= √3 × \(\frac{1}{√3- 1 }\) - 1
= √3 × \(\frac{√3+ 1}{2 }\) - 1
= \(\frac{√3+ 1}{2 }\)