Practicing Success
Practicing Success
CUET Preparation Today
If $1 + tan θ = \sqrt{3}$, then $\sqrt{3} cot θ -1$ = _________. |
$\frac{\sqrt{3}+1}{2}$ $\frac{\sqrt{3}-1}{2}$ $\frac{2\sqrt{3}-1}{2}$ $\frac{2\sqrt{3}+1}{2}$ |
$\frac{\sqrt{3}+1}{2}$ |
1 + tan θ = √3 tan θ = √3- 1 Now, √3.cotθ - 1 = √3 × \(\frac{1}{√3- 1 }\) - 1 = √3 × \(\frac{√3+ 1}{2 }\) - 1 = \(\frac{√3+ 1}{2 }\) |
