If for the following data:

the equation of the straight line trend is $y = 45.143 + 1.036(x-2003)$, then the trend value for the year 2004 is

46.18

The correct answer is Option (1) → 46.18 **

Given trend equation:

$y = 45.143 + 1.036(x - 2003)$

For year 2004:

$x - 2003 = 1$

So,

$y = 45.143 + 1.036(1)$

$y = 45.143 + 1.036$

$y = 46.179$

The trend value for the year 2004 is 46.179.