Practicing Success
A sum of money was lent in two parts in the ratio 4 : 5 for 4 years and 5 years respectively, both at the rate of 8% per annum simple interest. If the difference between the interests earned from the two parts is ₹ 4680, then what was the total sum lent(in ₹)? |
58500 42120 46800 65000 |
58500 |
Money was lent in two parts in the ratio of 4:5 first part Principal (P)1 = 4x Rate (R)1 = 8% Time (T)1 = 4 years second part Principal (P)2 = 5x Rate (R)2 = 8% Time (T)2 = 5 years ATQ, Difference of Interest = Rs 4680 I2 - I1 = 4680 \(\frac{P2×R2×T2}{100}\) - \(\frac{P1×R1×T1}{100}\) = 4680 \(\frac{5x×8×5}{100}\) - \(\frac{4x×8×4}{100}\) = 4680 \(\frac{200x}{100}\) - \(\frac{128x}{100}\) = 4680 \(\frac{72x}{100}\) = 4680 x = \(\frac{4680×100}{72}\) x = 6500 P1+P2 4x+5x = 9x 9×6500 Rs 58500 |