Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Probability Distributions

Question:

The Probability distribution of a random variable X is given as :

X: 0 1 2 3 4
P(X): K 2K 4K 5K 7K

The mean of the distribution is :

Options:

$\frac{23}{19}$

$\frac{3}{2}$

$\frac{33}{17}$

$\frac{53}{19}$

Correct Answer:

$\frac{53}{19}$