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If a + \(\frac{1}{a + 3}\) = 11 Then find , (a + 3)3 + \(\frac{1}{(a + 3)^3}\) |
2700 2702 272 270 |
2702 |
Given = a + \(\frac{1}{a + 3}\) = 11 By adding 3 on both sides we get, (a + 3) + \(\frac{1}{a + 3}\) = 11 + 3 = 14 (a + 3)3 + \(\frac{1}{(a + 3)^3}\) = 143 - 3 × 14 = 2702
Note - if x + \(\frac{1}{x}\) = a then x3 + \(\frac{1}{x^3}\) = a3 - 3a |
