By using the determinants the area of the triangle with vertices (0, 0), (0, 1) and (1, 0) is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{1}{2}$
so area of $Δ=\frac{1}{2}\begin{vmatrix}0&0&1\\0&1&1\\1&0&1\end{vmatrix}$
$=\frac{1}{2}$ sq. units