If \(\frac{a}{1}\) = \(\frac{b}{13}\) = \(\frac{c}{7}\)
then find (\(\frac{a + b }{a + b + c }\)).
Answer & explanation
Correct answer: option 2
Given, \(\frac{a}{1}\) = \(\frac{b}{13}\) = \(\frac{c}{7}\)
Here we can directly conclude that
a = 1, b = 13, c = 7, hence
⇒ (\(\frac{a + b }{a + b + c }\)) = (\(\frac{1 + 13}{1 + 13 + 7 }\)) = \(\frac{2}{3}\)