If \(\frac{a}{1}\) = \(\frac{b}{13}

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If \(\frac{a}{1}\) = \(\frac{b}{13}\) = \(\frac{c}{7}\)

then find (\(\frac{a + b }{a + b + c }\)).

Options:

\(\frac{5}{3}\)

\(\frac{2}{3}\)

\(\frac{2}{13}\)

\(\frac{7}{3}\)

Correct Answer:

\(\frac{2}{3}\)

Explanation:

Given, \(\frac{a}{1}\) = \(\frac{b}{13}\) = \(\frac{c}{7}\)

Here we can directly conclude that

a = 1, b = 13, c = 7, hence

⇒ (\(\frac{a + b }{a + b + c }\)) = (\(\frac{1 + 13}{1 + 13 + 7 }\))= \(\frac{2}{3}\)