Practicing Success
If the equation of a line PQ is $\frac{x+1}{2}=\frac{2-y}{5}=\frac{z+6}{7}$, then the direction cosines of a line parallel to PQ are: |
$\frac{2}{\sqrt{78}},\frac{5}{\sqrt{78}},\frac{7}{\sqrt{78}}$ $\frac{-5}{\sqrt{78}},\frac{-2}{\sqrt{78}},\frac{7}{\sqrt{78}}$ $\frac{5}{\sqrt{78}},\frac{-2}{\sqrt{78}},\frac{7}{\sqrt{78}}$ $\frac{2}{\sqrt{78}},\frac{-5}{\sqrt{78}},\frac{7}{\sqrt{78}}$ |
$\frac{2}{\sqrt{78}},\frac{-5}{\sqrt{78}},\frac{7}{\sqrt{78}}$ |
Line : $\frac{x+1}{2}=\frac{2-y}{5}=\frac{z+6}{7}$ ⇒ line : $\frac{x+1}{2}=\frac{y-2}{-5}=\frac{z+6}{7}$ vector parallel to this is $2\hat i-5\hat j+7\hat k$ unit vector = $\frac{2\hat i-5\hat j+7\hat k}{\sqrt{2^2+(-5)^2+7^2}}=\frac{2\hat i-5\hat j+7\hat k}{\sqrt{78}}$ Direction cosines $\frac{2}{\sqrt{78}},\frac{-5}{\sqrt{78}},\frac{7}{\sqrt{78}}$ |