In Young's double slit experiment, interference pattern is found to have an intensity ratio between bright and dark fringes as 9. Then amplitude ratio will be
Answer & explanation
Correct answer: option 2
$a_{max}=a_1+a_2;\,a_{min}=a_1-a_2$
$∴\frac{I_{max}}{I_{min}}=\frac{(a_1+a_2)^2}{(a_1-a_2)^2}=\frac{9}{1}⇒a_1=2$ and $a_2=1$
$∴\frac{a_1}{a_2}=\frac{2}{1}=2$