CUET Preparation Today
The area of the region bounded by the curve $x=y^2$, y-axis and the line y = 3 and y = 4 is: |
$\frac{11}{3}$ sq. units $\frac{23}{3}$ sq. units $\frac{37}{3}$ sq. units $\frac{55}{3}$ sq. units |
$\frac{37}{3}$ sq. units |
The correct answer is Option (3) → $\frac{37}{3}$ sq. units
So area = $\int\limits_3^4y^2dy=\left[\frac{y^3}{3}\right]_3^4$ $=\frac{37}{3}$ sq. units |
