Match List – I with List – II.
|
List - I |
List - II |
|
(A) $\oint \overrightarrow{B} . \overrightarrow{dA}=0$ |
(I) Gauss's Law of electricity |
|
(B) $\oint \overrightarrow{E} . \overrightarrow{dA}= \frac{Q}{\epsilon_{o}}$ |
(II) Gauss's Law of magnetism |
|
(C) $\oint \overrightarrow{B} . \overrightarrow{d l}=\mu_{o} i_{c}+\mu_{o} \epsilon_{o} \frac{d \phi_{E}}{dt}$ |
(III) Faraday's Law |
|
(D) $\oint \overrightarrow{E} . \overrightarrow{d l}=-\frac{d \phi_{B}}{dt}$ |
(IV) Ampere-Maxwell Law |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
|
List - I |
List - II |
|
(A) $\oint \overrightarrow{B} . \overrightarrow{dA}=0$ |
(II) Gauss's Law of magnetism |
|
(B) $\oint \overrightarrow{E} . \overrightarrow{dA}= \frac{Q}{\epsilon_{o}}$ |
(I) Gauss's Law of electricity |
|
(C) $\oint \overrightarrow{B} . \overrightarrow{d l}=\mu_{o} i_{c}+\mu_{o} \epsilon_{o} \frac{d \phi_{E}}{dt}$ |
(IV) Ampere-Maxwell Law |
|
(D) $\oint \overrightarrow{E} . \overrightarrow{d l}=-\frac{d \phi_{B}}{dt}$ |
(III) Faraday's Law |