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Three capacitors, $C_1, C_2, C_3$ are connected in series. This combination is connected in parallel with capacitor $C_4$. $C_1= C_2 =C_3= 30 μF$ and $C_4 = 10 μF$. Now a potential 400 V is applied across the combination. The total charge across the combination of capacitors is |
$8 × 10^{-3} C$ $4 × 10^{-3} C$ $3.6 × 10^{-3} C$ $4 × 10^{-2} C$ |
$8 × 10^{-3} C$ |
The correct answer is Option (1) → $8 × 10^{-3} C$ |
