Practicing Success
Practicing Success
CUET Preparation Today
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$\text{Current flowing at time t is given by I } = \frac{E}{R} e^{\frac{-tR}{L}}$ $\text{Charge passes through the battery between t=0 and t = }\frac{L}{R} \text{ is } Q = \int_{0}^{\frac{L}{R}}{I dt} = \int_{0}^{\frac{L}{R}}{\frac{E}{R} e^{\frac{-tR}{L}} dt} = \frac{EL}{eR^2} = \frac{EL}{2.7R^2}$ |
