The number of Faradays required to produce one mole of water from hydrogen-oxygen fuel cell containing aqueous alkali as electrolyte is

2

At anode: \(H_2 (g)  +  2OH^−(aq) \rightarrow 2H_2O (l)  +  2e^−\)

At Cathode : \(O_2(g)  +  2H_2O (l)  +  4e^−\rightarrow 4OH^− (aq)\)

Overall: \(2H_2 (g)  +  O_2 (g)  \rightarrow  2H_2O (l)\)

4F of charge is required to produce 2 moles of \(H_2O\).

Thus, 2 moles of charge is required to produce 1 mole of \(H_2O\).

Therefore, the number of Faraday required = 2F.

Therefore, the correct answer is (3) 2.