A pair of dice is thrown. What is the probability of getting the sum of numbers on the two faces an odd-prime number?

$\frac{7}{18}$

A pair of dice is thrown

Sample Space {(11) (12)....(16), .........,(64)(65)(66)}

Number of total outcomes = 36

sum as an odd prime numbers = 3, 5, 7, 11

Chances of getting sum as an odd prime numbers {(12)(21)(14)(41)(23)(32)(25)(52)(34)(43)(16)(61)(56)(65)}

Required probability = 14/36 = 7/18

The correct answer is Option (1) → $\frac{7}{18}$