Tangent drawn from a point P, touches the circle at Q. O is the centre of this circle. If PQ = 12 cm and OQ = 5 cm, then what is the value of OP?
Answer & explanation
Correct answer: option 4
According tot the concept,
\(\angle\)OQP = \({90}^\circ\)
Hence, OP is the hypotenuse of \(\Delta \)OQP which is a right angled triangle.
Now, OP = \(\sqrt { {12 }^{2 } + {5 }^{2 } }\) = 13 cm
Therefore, OP is 13 cm.