If \(f(x)=\frac{4^{x}}{4^{x}+2}\) then \(f(x)+f(1-x)\) is equal to

\(0\) \(-1\) \(1\) \(4\)

\(1\)

$f(x)=\frac{4^{x}}{4^{x}+2}⇒f(1-x)=\frac{4^{1-x}}{4^{1-x}+2}⇒\frac{4}{4+2×4x}=\frac{2}{2+4x}$ so $f(x)+f(1-x)=\frac{4^{x}+2}{4^{x}+2}=1$