Two particles A1 and A2 of masses m1 and m2 (m1>m2) have the same de broglie wave-length. Then :
Answer & explanation
Correct answer: option 3
Use :
\(\lambda\) = \(\frac{h}{p}\) ⇒ p = \(\frac{h}{\lambda}\)
E = \(\frac{1}{2}\) \(\frac{p^2}{m}\)
Two particles A1 and A2 of masses m1 and m2 (m1>m2) have the same de broglie wave-length. Then :
Correct answer: option 3
Use :
\(\lambda\) = \(\frac{h}{p}\) ⇒ p = \(\frac{h}{\lambda}\)
E = \(\frac{1}{2}\) \(\frac{p^2}{m}\)