Two particles A1 and A2 of masses m1 and m2 (m1>m2) have the same de broglie wave-length. Then :

their momenta are the same their energies are the same energy of A1 is less than the energy of A2 energy of A2 is less than the energy of A1

energy of A1 is less than the energy of A2

Use : \(\lambda\) = \(\frac{h}{p}\) ⇒ p = \(\frac{h}{\lambda}\) E = \(\frac{1}{2}\) \(\frac{p^2}{m}\)