Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

Acidified solution of K2Cr2O7 oxidises which of the following?

Options:

Sulphate ions

Sulphite ions

Nitrate ions

Ferric ions

Correct Answer:

Sulphite ions

Explanation:

Cr2O72- + 3SO32- + 8H+ → 2Cr3+ + 3SO42- + 4H2O

K2Cr2O7 can oxidise SO32- (Sulphite ions) to SO42- (Sulphate ions)

Nitrate ion, ferric ion, and borate ions are already in their highest oxidation state thus they cannot be further oxidized.