CUET Preparation Today
If $A=\begin{bmatrix}2&3\\1&-4\end{bmatrix}$ and $B =\begin{bmatrix}1&-2\\-1&3\end{bmatrix}$, then $B^{-1} A^{-1}$ is equal to: |
$-\frac{1}{11}=\begin{bmatrix}14&5\\5&1\end{bmatrix}$ $\frac{1}{11}=\begin{bmatrix}15&11\\1&0\end{bmatrix}$ $\frac{1}{11}=\begin{bmatrix}14&5\\5&1\end{bmatrix}$ $-\frac{1}{11}=\begin{bmatrix}15&11\\1&0\end{bmatrix}$ |
$\frac{1}{11}=\begin{bmatrix}14&5\\5&1\end{bmatrix}$ |
The correct answer is Option (3) → $\frac{1}{11}=\begin{bmatrix}14&5\\5&1\end{bmatrix}$ |
