In a ΔABC, the bisector of ∠B and ∠C meet at point O, inside the triangle. If ∠BOC = 106°, then the measure of ∠A is?
Answer & explanation
Correct answer: option 2
⇒ ∠BOC = 90° + \(\frac{1}{2}\) ∠A
⇒ 106° = 90° + \(\frac{1}{2}\) ∠A
⇒ ∠A = 32°
In a ΔABC, the bisector of ∠B and ∠C meet at point O, inside the triangle. If ∠BOC = 106°, then the measure of ∠A is?
Correct answer: option 2
⇒ ∠BOC = 90° + \(\frac{1}{2}\) ∠A
⇒ 106° = 90° + \(\frac{1}{2}\) ∠A
⇒ ∠A = 32°