What will be the frequency and wave numberof a yellow light having a wavelength of \(\overset{o}{A}\)?

\(\nu \text{ = 5.0 × }10^{14}Hz\text{,   }\overset{–}{\nu} \text{ = 1.666 × }10^6m^{-1}\)

The correct answer is option 2. \(\nu \text{ = 5.0 × }10^{14}Hz\text{,   }\overset{–}{\nu} \text{ = 1.666 × }10^6m^{-1}\).

\(\text{Here,     }\lambda \text{ = 6000}\overset{o}{A} \text{= 6000 × }10^{-10}\text{ }m\text{     and ,   c= 3 ×}10^8ms^{-1}\)

∴ \(\text{Frequency, }\nu \text{ = }\frac{c}{\lambda}\text{ = }\frac{3 \text{ × }10^8\text{ m}s^{-1}}{6000 \text{ × }10^{-10} m}\)

\(\nu \text{ = 0.5 × }10^{15}Hz \text{ = 5.0 × }10^{14}Hz\)

\(\text{Wave number, }\overset{–}{\nu}\text{ = }\frac{1}{\lambda}\text{ = }\frac{1}{6000 \text{ × }10^{-10}m}\)

\(\overset{–}{\nu}\text{ = 0.1666 × }10^7m^{-1}\)

\(\overset{–}{\nu}\text{ = 1.666 × }10^6m^{-1}\)