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If focal length of a concave lens is 50 cm, then the power of the lens would be |
+5 D -5 D +2 D -2 D |
-2 D |
The correct answer is Option (4) → -2 D Given: Focal length, $f = -50 \text{ cm} = -0.5 \text{ m}$ Formula: $P = \frac{1}{f}$ $P = \frac{1}{-0.5} = -2 \, \text{D}$ Therefore, the power of the concave lens is $-2 \, \text{dioptres}$. |
