The HCF of $\frac{3}{4},\frac{7}{8}$ and $\frac{13}{14}$ is:
Answer & explanation
Correct answer: option 2
HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)
The given fractions are : $\frac{3}{4},\frac{7}{8}$ and $\frac{13}{14}$.
LCM of 4, 8, 14 = 56
HCF of 3, 7, 13= 1
The HCF of $\frac{3}{4},\frac{7}{8}$ and $\frac{13}{14}$. is = \(\frac{1}{56}\)