Angle between the internal bisectors of two angles $\angle B$ and $\angle C$ of a $\triangle A B C$ is $132^{\circ}$, then the value of $\angle A$ is:

84°

\(\angle\)BIC = \({132}^\circ\)

\(\angle\)BIC = \({90}^\circ\) + \(\frac{1}{2}\)\(\angle\)A

\(\angle\)A/2 = (\({132}^\circ\) - \({90}^\circ\))

= \(\angle\)A/2 = \({42}^\circ\)

= \(\angle\)A = 42 x 2

= \(\angle\)A = \({84}^\circ\)

Therefore, \(\angle\)A is \({84}^\circ\).