Angle between the internal bisectors of two angles $\angle B$ and $\angle C$ of a $\triangle A B C$ is $132^{\circ}$, then the value of $\angle A$ is:
Answer & explanation
Correct answer: option 3
\(\angle\)BIC = \({132}^\circ\)
\(\angle\)BIC = \({90}^\circ\) + \(\frac{1}{2}\)\(\angle\)A
\(\angle\)A/2 = (\({132}^\circ\) - \({90}^\circ\))
= \(\angle\)A/2 = \({42}^\circ\)
= \(\angle\)A = 42 x 2
= \(\angle\)A = \({84}^\circ\)
Therefore, \(\angle\)A is \({84}^\circ\).