An oxidation of phenol with chromic acid produces
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Benzoquinone
Oxidation of Phenol
Phenol ($\text{C}_6\text{H}_5\text{OH}$) is easily oxidized due to the presence of the activating hydroxyl group ($\text{-OH}$).
- Reagent: Chromic acid ($\text{H}_2\text{CrO}_4$) is a strong oxidizing agent, often generated in situ from sodium dichromate ($\text{Na}_2\text{Cr}_2\text{O}_7$) or potassium dichromate ($\text{K}_2\text{Cr}_2\text{O}_7$) in acidic medium ($\text{H}_2\text{SO}_4$).
- Reaction: When phenol is treated with chromic acid, it undergoes oxidation to form 1,4-Benzoquinone (or simply p-Benzoquinone).
The reaction converts the aromatic ring system into a non-aromatic, cyclic dione structure. This is the characteristic product when strong oxidizing agents are used under these conditions.
The correct option is: Benzoquinone