If the sum of two numbers is 60 and the HCF and LCM of these numbers are 6 and 150 , then the sum of their reciprocals is- |
\(\frac{1}{15}\) \(\frac{1}{12}\) \(\frac{1}{18}\) \(\frac{1}{16}\) |
\(\frac{1}{15}\) |
Let the two numbers be $a$ and $b$. Given:
We know: $ab = \text{HCF} \times \text{LCM} = 6 \times 150 = 900$ The sum of their reciprocals is: $\frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab} = \frac{60}{900} = \frac{1}{15}$ |