22 boys, working together, can complete a work in 10 days, whereas 25 boys and 12 girls take 8 days to complete the same work In how many days can only 6 girls, working together, complete the same work?

176

22 Boys = 10 days,

25 Boys + 12 Girls = 8 days,

⇒ 22B x 10 = (25B + 12G) x 8 

⇒ 110B = 100B + 48G

⇒ 10B = 48G

⇒ B : G = 48 : 10 = 24 : 5  (Efficiencies) 

⇒ Total work = 22(24) x 10 = 528 x 10 = 5280 units,

⇒ Time required by 6 Girls to complete total work = \(\frac{5280}{6(5)}\) = 176 days,   ..(\(\frac{Work}{Efficiency}\) = Time)