22 boys, working together, can complete a work in 10 days, whereas 25 boys and 12 girls take 8 days to complete the same work In how many days can only 6 girls, working together, complete the same work?
Answer & explanation
Correct answer: option 4
22 Boys = 10 days,
25 Boys + 12 Girls = 8 days,
⇒ 22B x 10 = (25B + 12G) x 8
⇒ 110B = 100B + 48G
⇒ 10B = 48G
⇒ B : G = 48 : 10 = 24 : 5 (Efficiencies)
⇒ Total work = 22(24) x 10 = 528 x 10 = 5280 units,
⇒ Time required by 6 Girls to complete total work = \(\frac{5280}{6(5)}\) = 176 days, ..(\(\frac{Work}{Efficiency}\) = Time)