Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

Convex lens of 10 cm focal length is combined with a concave lens of 6 cm focal length. Find the focal length of the combination.

Options:

15 cm

 – 15 cm

30 cm  

 – 30 cm

Correct Answer:

15 cm

Explanation:

$ f_1 = 10cm , f_2 = -6cm , F= ?$

$ \frac{1}{F} = \frac{1}{f_1} + \frac{1}{f_2} = \frac{1}{6} - \frac{1}{10} = \frac{5 - 3}{30} = \frac{1}{15}$

$\Rightarrow F = 15cm$