Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

If $A = \begin{bmatrix} \cos α & \sin α\\ -\sin α & \cos α \end{bmatrix}$, then :

Options:

A'A = I

A'A = 0

A'A = 2I

A'A = -I

Correct Answer:

A'A = I

Explanation:

$A = \begin{bmatrix} \cos α & \sin α\\ -\sin α & \cos α \end{bmatrix}$

$A' = \begin{bmatrix} \cos α & -\sin α\\ \sin α & \cos α \end{bmatrix}$

So  $AA' = \begin{bmatrix} \cos α & \sin α\\ -\sin α & \cos α \end{bmatrix} \begin{bmatrix} \cos α & -\sin α\\ \sin α & \cos α \end{bmatrix}$

$AA' = \begin{bmatrix} \cos^2 α + \sin^2 α & -\cos α \sin α + \cos α \sin α\\ -\cos α \sin α + \cos α \sin α & \cos^2α + \sin^2α \end{bmatrix}$

$= \begin{bmatrix} 1 & 0\\ 0 & 1 \end{bmatrix} = I$