Practicing Success
Match List - I with List - II.
Choose the correct answer from the options given below : |
(A) - (IV), (B) - (I), (C) - (II), (D) - (III) (A) - (IV), (B) - (III), (C) - (I), (D) - (II) (A) - (II), (B) - (IV), (C) - (I), (D) - (III) (A) - (IV), (B) - (III), (C) - (II), (D) - (I) |
(A) - (IV), (B) - (I), (C) - (II), (D) - (III) |
(A) $\hat i, \hat j, \hat k$ $\hat i×\hat j=\hat k ⇒\hat j×\hat k=\hat i$,$\hat k ×\hat i=\hat j$ Do i product. $\hat i.\hat i$, $\hat j.\hat j$ = 1 $\begin{matrix}\hat i×\hat j=\hat k&\hat j × \hat i = -\hat k\\\hat j×\hat k=\hat i&\hat k×\hat i=-\hat i\\\hat k ×\hat i=\hat j&\hat i×\hat k-\hat j\end{matrix}$ $=\hat i.(\hat j ×\hat k)+\hat j.(\hat i ×\hat k)+\hat k.(\hat i×\hat j)$ $=\hat i.(\hat i)+\hat j.(-\hat j)+\hat k.(\hat k)$ $=\hat i.\hat i-\hat j.\hat j+\hat k.\hat k$ ⇒ 1 - 1 + 1 = 1 (B) If $|\vec{a}|=10$, $|\vec{b}|=2$, $\vec{a}.\vec{b}=12$, then the value of $|\vec{a}×\vec{b}|$ is $\vec a.\vec b=|\vec a||\vec b|.cosθ⇒12=10×2cosθ$ $⇒cosθ=\frac{12}{20}=\frac{3}{5}$ $⇒sinθ=\sqrt{1-cos^2θ}=\sqrt{1-\frac{9}{25}}⇒sinθ=±\frac{4}{5}$ $∴|\vec a×\vec b|=|\vec a||\vec b||sinθ|⇒10×2×\frac{4}{5}$ (C) If θ in the angle between two vectors $\vec{a}$ and $\vec{b}$, then the value of θ, for which $\vec{a}.\vec{b}=|\vec{a}×\vec{b}|$ is value for θ $=\frac{\pi}{4}$ (D) If $\vec{a}$ and $\vec{b}$ are perpendicular and $\vec{a}=2\hat{i}+4\hat{j}+λ\hat{k}$ and $\vec{b}=3\hat{i}-5\hat{j}+\hat{k}$ then the value of λ is: given vectors are perpendicular $∴ (2\hat{i}+4\hat{j}+λ\hat{k}).(3\hat{i}-5\hat{j}+\hat{k})$ $(2)(3)+(4)(5)+(λ)(1)$ $6+(-20)+λ⇒6-20+λ⇒14=λ$ So, correct option is 1. -i.e., (A) - (IV), (B) - (I), (C) - (II), (D) - (III) |