Practicing Success
Practicing Success
CUET Preparation Today
If $x^y=e^{x-y}, x> 0, $ then $\frac{dy}{dx}$ is equal to : |
$-\left[\frac{log_ex}{(1+log_ex)^2}\right]$ $\frac{log_ex}{(1+log_ex)^2}$ $-\frac{log_ex}{1+log_ex}$ $\frac{log_ex}{1+log_ex}$ |
$\frac{log_ex}{(1+log_ex)^2}$ |
