Practicing Success
A current carrying square loop is placed near an infinitely long current carrying wire as shown in figure. The torque acting on the loop is: |
$\frac{\mu_0}{2 \pi}\left(\frac{I_1 I_2 a}{2}\right)$ $\frac{\mu_0 I_1 I_2 a}{2 \pi}$ $\frac{\mu_0 I_1 I_2}{2 \pi} \log (2)$ Zero |
Zero |
The correct answer is Option (4) → Zero Torque acting on loop, $\vec{\tau}=\vec{M} \times \vec{B}$, where $\vec{M}$ is the magnetic moment and $\vec{B}$ is the external magnetic field. $|\tau|=M B \sin \theta$ Since $\theta=0^{\circ} \Rightarrow \tau=0$, where $\theta$ is the angle between the magnetic moment and external magnetic field. |