CUET Preparation Today
If cosθ=\(\frac{1}{\sqrt {10}}\) then find the value of sec2θ + tanθ. |
45 26 39 13 |
13 |
cosθ=\(\frac{1}{\sqrt {10}}\)=\(\frac{B}{H}\) P=\(\sqrt {(\sqrt {10})^2-(1)^2}\) (H2 = B2 + P2) P=\(\sqrt {10-1}\) P = 3 Now, sec2θ + tanθ =(\(\frac{\sqrt {10}}{1}\))2+\(\frac{3}{1}\) = 10 + 3 = 13 |
