If a : b = 4 : 3 , then find the value o

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Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

If a : b = 4 : 3 , then find the value of $\frac{4a+2b }{2a+4b}$ .

Options:

$\frac{21}{10}$

$\frac{5}{3}$

$\frac{11}{13}$

$\frac{11}{10}$

Correct Answer:

$\frac{11}{10}$

Explanation:

a : b = 4 : 3

$\frac{4a\;+\;2b }{2a\;+\;4b}$= $\frac{4×4\;+\;2×3 }{2×4\;+\;4×3}$ = $\frac{22}{20}$ = $\frac{11}{10}$