A shopkeeper has 1 quintal of wheat, part of which she sells at 18% gain and the rest at 28% gain. In total she gains 24%. What is the quantity of wheat sold at 18% and 28% ? |
18% = 40 kg and 28% = 50 kg 18% = 40 kg and 28% = 50 kg 18% = 50 kg and 28% = 60 kg 18% = 40 kg and 28% = 60 kg |
18% = 40 kg and 28% = 60 kg |
The correct answer is option (4) : 18% = 40 kg and 28% = 60 kg Given, Total quantity of wheat = 1 quintal $= 100 \, kg $ $c= 18$% profit $m= 24$% profit $d= 28$% profit $∴\frac{\text{Quan. of wheat at 18% profit}}{\text{Quan. of wheat at 28% profit}}=\frac{d-m}{m-c}=\frac{4}{6}=\frac{2}{3}$ So, quan of wheat sold at 18% profit $=\frac{2}{5}×100= 40\, kg $ at 28% profit $=\frac{3}{5}×100= 60 kg $ |