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-- Mathematics - Section A
Definite Integration
If \(f(a+x)=f(x)\) then \(\int_{0}^{na}f(x)dx= \) (where \(n\in N\))
\((n-1)\int_{0}^{a}f(x)dx\)
\(n\int_{0}^{a}f(x)dx\)
\(\int_{0}^{(n-1)a}f(x)dx\)
\(\int_{0}^{a}f(x)dx\)