A container of 50 liters was full of milk. 5 liters liquid drawn off and replaced by water and this process is repeated two times more. Find quantity of milk in mixture now (in liters).

36.45

We have,

A vessel has 50 liters of milk.

5 liters of water is drawn out from this vessel and replaced by milk.

This process was repeated further two times.

Amount of milk left after 3 operations = 50 [1 – (\(\frac{5}{50}\))]³

= 50 × \(\frac{9}{10}\) × \(\frac{9}{10}\) × \(\frac{9}{10}\) = 36.45