Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Matrices

Question:

The system of equations 3x + 4y = 5, 6x + 7y = -8 is written in matrix from as

Options:

$\left[\begin{array}{ll}3 & 4 \\ 6 & 7\end{array}\right]\left[\begin{array}{ll}x & y\end{array}\right]=\left[\begin{array}{ll}5 & -8\end{array}\right]$

$\left[\begin{array}{ll}3 & 6 \\ 4 & 7\end{array}\right]\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{c}5 \\ -8\end{array}\right]$

$\left[\begin{array}{l}x \\ y\end{array}\right]\left[\begin{array}{ll}3 & 4 \\ 6 & 7\end{array}\right]=\left[\begin{array}{c}5 \\ -8\end{array}\right]$

$\left[\begin{array}{ll}x & y\end{array}\right]\left[\begin{array}{ll}3 & 6 \\ 4 & 7\end{array}\right]=\left[\begin{array}{ll}5 & -8\end{array}\right]$

Correct Answer:

$\left[\begin{array}{ll}x & y\end{array}\right]\left[\begin{array}{ll}3 & 6 \\ 4 & 7\end{array}\right]=\left[\begin{array}{ll}5 & -8\end{array}\right]$