A battery of emf 12 V and internal resistance \( 3\,\Omega \) is connected to a resistor. If the current in the circuit is 0.8 A, the terminal voltage of the battery will be
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 9.6 V
When a current is drawn, part of the emf is lost across the internal resistance, so the terminal voltage is \( V = E - I r \).
\( \displaystyle V = 12 - (0.8 \times 3) = 12 - 2.4 = 9.6\,\mathrm{V} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
