Integral curve satisfying $y'=\frac{x^2+y^2}{x^2-y^2},y(1)≠1$ has the slope at the point (1, 0) of the curve equal to:

$-\frac{5}{3}$ -1 1 $\frac{5}{3}$

1

$\frac{dy}{dx}=\frac{x^2+y^2}{x^2-y^2}⇒\frac{dy}{dx}|_{at\,(1,0)}=1$